std::filesystem::path::compare (3) - Linux Manuals

std::filesystem::path::compare: std::filesystem::path::compare

NAME

std::filesystem::path::compare - std::filesystem::path::compare

Synopsis


int compare( const path& p ) const noexcept; (1) (since C++17)
int compare( const string_type& str ) const; (2) (since C++17)
int compare( std::basic_string_view<value_type> str ) const;
int compare( const value_type* s ) const; (3) (since C++17)


Compares the lexical representations of the path and another path.
1) If root_name().native().compare(p.root_name().native()) is nonzero, returns that value.
Otherwise, if has_root_directory() != p.has_root_directory(), returns a value less than zero if has_root_directory() is false and a value greater than zero otherwise.
Otherwise returns a value less than, equal to or greater than 0 if the relative portion of the path (relative_path()) is respectively lexicographically less than, equal to or greater than the relative portion of p (p.relative_path()). Comparison is performed element-wise, as if by iterating both paths from begin() to end() and comparing the result of native() for each element.
2) Equivalent to compare(path(str)).
3) Equivalent to compare(path(s)).

Parameters


p - a path to compare to
str - a string or string view representing path to compare to
s - a null-terminated string representing path to compare to

Return value


A value less than 0 if the path is lexicographically less than the given path.
A value equal to 0 if the path is lexicographically equal to the given path.
A value greater than 0 if the path is lexicographically greater than the given path.

Exceptions


2-3) (none)

Notes


For two-way comparisons, binary_operators may be more suitable.

Example


// Run this code


  #include <iostream>
  #include <filesystem>
  namespace fs = std::filesystem;
  void demo(int rc, fs::path p1, fs::path p2) {
      if(rc < 0) std::cout << p1 << " < " << p2 << '\n';
      else if(rc > 0) std::cout << p1 << " > " << p2 << '\n';
      else if(rc == 0) std::cout << p1 << "==" << p2 << '\n';
  }
  int main() {
      fs::path p1 = "/a/b/"; // as if "a/b/." for lexicographical iteration
      fs::path p2 = "/a/b/#";
      demo(p1.compare(p2), p1, p2);
      demo(p1.compare("a/b/_"), p1, "a/b/_");
  }

Output:


  "/a/b/" > "/a/b/#"
  "/a/b/" < "a/b/_"


Defect reports


The following behavior-changing defect reports were applied retroactively to previously published C++ standards.


DR Applied to Behavior as published Correct behavior
LWG_2936 C++17 compared all path elements directly root name and root directory handled separately

See also


operator==
operator!= lexicographically compares two paths
operator< (function)
operator<=
operator>
operator>=