std::chrono::weekday::operator+=,std::chrono::weekday::operator-= (3) - Linux Manuals

std::chrono::weekday::operator+=,std::chrono::weekday::operator-=: std::chrono::weekday::operator+=,std::chrono::weekday::operator-=

NAME

std::chrono::weekday::operator+=,std::chrono::weekday::operator-= - std::chrono::weekday::operator+=,std::chrono::weekday::operator-=

Synopsis

constexpr std::chrono::weekday& operator+=(const std::chrono::days& d) noexcept; (1) (since C++20)
constexpr std::chrono::weekday& operator-=(const std::chrono::days& d) noexcept; (2) (since C++20)

Adds or subtracts d.count() from the weekday value, reducing the result modulo 7 to an integer in the range [0, 6].
1) Performs *this = *this + d;
2) Performs *this = *this - d;

Return value

A reference to this weekday after modification.

Notes

After a call to one of these functions, ok() is always true if no overflow occurred during the operation.

Example

 This section is incomplete
 Reason: no example