std::chrono::month::operator+=,std::chrono::month::operator-= (3) - Linux Manuals

std::chrono::month::operator+=,std::chrono::month::operator-=: std::chrono::month::operator+=,std::chrono::month::operator-=

NAME

std::chrono::month::operator+=,std::chrono::month::operator-= - std::chrono::month::operator+=,std::chrono::month::operator-=

Synopsis

constexpr std::chrono::month& operator+=(const std::chrono::months& m) noexcept; (1) (since C++20)
constexpr std::chrono::month& operator+=(const std::chrono::months& m) noexcept; (2) (since C++20)

Adds or subtracts m.count() from the month value, reducing the result modulo 12 to an integer in the range [1, 12].
1) Performs *this = *this + m;
2) Performs *this = *this - m;

Return value

A reference to this month after modification.

Notes

After a call to one of these functions, ok() is always true if no overflow occurred during the operation.

Example

 This section is incomplete
 Reason: no example