std::basic_stringbuf<CharT,Traits,Allocator>::operator= (3) - Linux Manuals

std::basic_stringbuf<CharT,Traits,Allocator>::operator=: std::basic_stringbuf<CharT,Traits,Allocator>::operator=

NAME

std::basic_stringbuf<CharT,Traits,Allocator>::operator= - std::basic_stringbuf<CharT,Traits,Allocator>::operator=

Synopsis

std::basic_stringbuf& operator=( std::basic_stringbuf&& rhs ); (1) (since C++11)
std::basic_stringbuf& operator=( const std::basic_stringbuf& rhs ) = delete; (2)

1) Move assignment operator: Moves the contents of rhs into *this. After the move, *this has the associated string, the open mode, the locale, and all other state formerly held by rhs. The six pointers of std::basic_streambuf in *this are guaranteed to be different from the corresponding pointers in the moved-from rhs unless null.
2) The copy assignment operator is deleted; basic_stringbuf is not CopyAssignable.

Parameters

rhs - another basic_stringbuf that will be moved from

Return value

*this

Example

// Run this code

  #include <sstream>
  #include <string>
  #include <iostream>

  int main()
  {

      std::istringstream one("one");
      std::ostringstream two("two");

      std::cout << "Before move, one = \"" << one.str() << '"'
                << " two = \"" << two.str() << "\"\n";

      *one.rdbuf() = std::move(*two.rdbuf());

      std::cout << "After move, one = \"" << one.str() << '"'
                << " two = \"" << two.str() << "\"\n";
  }

Output:

  Before move, one = "one" two = "two"
  After move, one = "two" two = ""