memmove (3) - Linux Manuals

memmove: copy memory area

NAME

memmove - copy memory area

SYNOPSIS

#include <string.h>

void *memmove(void *dest, const void *src, size_t n);

DESCRIPTION

The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied from the temporary array to dest.

RETURN VALUE

The memmove() function returns a pointer to dest.

ATTRIBUTES

For an explanation of the terms used in this section, see attributes(7).
InterfaceAttributeValue
memmove() Thread safetyMT-Safe

CONFORMING TO

POSIX.1-2001, POSIX.1-2008, C89, C99, SVr4, 4.3BSD.

COLOPHON

This page is part of release 5.10 of the Linux man-pages project. A description of the project, information about reporting bugs, and the latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.

SEE ALSO

bcopy(3), bstring(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)