deductionguidesforstd::deque (3) - Linux Manuals

deductionguidesforstd::deque: deductionguidesforstd::deque

NAME

deductionguidesforstd::deque - deductionguidesforstd::deque

Synopsis

Defined in header <deque>
template< class InputIt,
class Alloc = std::allocator<typename std::iterator_traits<InputIt>::value_type>> (since C++17)
deque(InputIt, InputIt, Alloc = Alloc())
-> deque<typename std::iterator_traits<InputIt>::value_type, Alloc>;

This deduction_guide is provided for deque to allow deduction from an iterator range. This overload only participates in overload resolution if InputIt satisfies LegacyInputIterator and Alloc satisfies Allocator.
Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type must exist and the expression std::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.

Example

// Run this code

  #include <deque>
  #include <vector>
  int main() {
     std::vector<int> v = {1, 2, 3, 4};

     // uses explicit deduction guide to deduce std::deque<int>
     std::deque x(v.begin(), v.end());

     // deduces std::deque<std::vector<int>::iterator>
     // first phase of overload resolution for list-initialization selects the candidate
     // synthesized from the initializer-list constructor; second phase is not performed and
     // deduction guide has no effect
     std::deque y{v.begin(), v.end()};
  }